Optimal. Leaf size=162 \[ -\frac{3 d^3 (c+d x) \sinh ^2(a+b x)}{2 b^4}+\frac{3 d^2 (c+d x)^2 \sinh (a+b x) \cosh (a+b x)}{2 b^3}-\frac{d (c+d x)^3 \sinh ^2(a+b x)}{b^2}+\frac{3 d^4 \sinh (a+b x) \cosh (a+b x)}{4 b^5}+\frac{(c+d x)^4 \sinh (a+b x) \cosh (a+b x)}{2 b}-\frac{d (c+d x)^3}{2 b^2}-\frac{3 d^4 x}{4 b^4}-\frac{(c+d x)^5}{10 d} \]
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Rubi [A] time = 0.104895, antiderivative size = 162, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {3311, 32, 2635, 8} \[ -\frac{3 d^3 (c+d x) \sinh ^2(a+b x)}{2 b^4}+\frac{3 d^2 (c+d x)^2 \sinh (a+b x) \cosh (a+b x)}{2 b^3}-\frac{d (c+d x)^3 \sinh ^2(a+b x)}{b^2}+\frac{3 d^4 \sinh (a+b x) \cosh (a+b x)}{4 b^5}+\frac{(c+d x)^4 \sinh (a+b x) \cosh (a+b x)}{2 b}-\frac{d (c+d x)^3}{2 b^2}-\frac{3 d^4 x}{4 b^4}-\frac{(c+d x)^5}{10 d} \]
Antiderivative was successfully verified.
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Rule 3311
Rule 32
Rule 2635
Rule 8
Rubi steps
\begin{align*} \int (c+d x)^4 \sinh ^2(a+b x) \, dx &=\frac{(c+d x)^4 \cosh (a+b x) \sinh (a+b x)}{2 b}-\frac{d (c+d x)^3 \sinh ^2(a+b x)}{b^2}-\frac{1}{2} \int (c+d x)^4 \, dx+\frac{\left (3 d^2\right ) \int (c+d x)^2 \sinh ^2(a+b x) \, dx}{b^2}\\ &=-\frac{(c+d x)^5}{10 d}+\frac{3 d^2 (c+d x)^2 \cosh (a+b x) \sinh (a+b x)}{2 b^3}+\frac{(c+d x)^4 \cosh (a+b x) \sinh (a+b x)}{2 b}-\frac{3 d^3 (c+d x) \sinh ^2(a+b x)}{2 b^4}-\frac{d (c+d x)^3 \sinh ^2(a+b x)}{b^2}-\frac{\left (3 d^2\right ) \int (c+d x)^2 \, dx}{2 b^2}+\frac{\left (3 d^4\right ) \int \sinh ^2(a+b x) \, dx}{2 b^4}\\ &=-\frac{d (c+d x)^3}{2 b^2}-\frac{(c+d x)^5}{10 d}+\frac{3 d^4 \cosh (a+b x) \sinh (a+b x)}{4 b^5}+\frac{3 d^2 (c+d x)^2 \cosh (a+b x) \sinh (a+b x)}{2 b^3}+\frac{(c+d x)^4 \cosh (a+b x) \sinh (a+b x)}{2 b}-\frac{3 d^3 (c+d x) \sinh ^2(a+b x)}{2 b^4}-\frac{d (c+d x)^3 \sinh ^2(a+b x)}{b^2}-\frac{\left (3 d^4\right ) \int 1 \, dx}{4 b^4}\\ &=-\frac{3 d^4 x}{4 b^4}-\frac{d (c+d x)^3}{2 b^2}-\frac{(c+d x)^5}{10 d}+\frac{3 d^4 \cosh (a+b x) \sinh (a+b x)}{4 b^5}+\frac{3 d^2 (c+d x)^2 \cosh (a+b x) \sinh (a+b x)}{2 b^3}+\frac{(c+d x)^4 \cosh (a+b x) \sinh (a+b x)}{2 b}-\frac{3 d^3 (c+d x) \sinh ^2(a+b x)}{2 b^4}-\frac{d (c+d x)^3 \sinh ^2(a+b x)}{b^2}\\ \end{align*}
Mathematica [A] time = 0.681253, size = 132, normalized size = 0.81 \[ \frac{10 \sinh (2 (a+b x)) \left (6 b^2 d^2 (c+d x)^2+2 b^4 (c+d x)^4+3 d^4\right )-20 b d (c+d x) \cosh (2 (a+b x)) \left (2 b^2 (c+d x)^2+3 d^2\right )-8 b^5 x \left (10 c^2 d^2 x^2+10 c^3 d x+5 c^4+5 c d^3 x^3+d^4 x^4\right )}{80 b^5} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.016, size = 910, normalized size = 5.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.2571, size = 516, normalized size = 3.19 \begin{align*} -\frac{1}{4} \,{\left (4 \, x^{2} - \frac{{\left (2 \, b x e^{\left (2 \, a\right )} - e^{\left (2 \, a\right )}\right )} e^{\left (2 \, b x\right )}}{b^{2}} + \frac{{\left (2 \, b x + 1\right )} e^{\left (-2 \, b x - 2 \, a\right )}}{b^{2}}\right )} c^{3} d - \frac{1}{8} \,{\left (8 \, x^{3} - \frac{3 \,{\left (2 \, b^{2} x^{2} e^{\left (2 \, a\right )} - 2 \, b x e^{\left (2 \, a\right )} + e^{\left (2 \, a\right )}\right )} e^{\left (2 \, b x\right )}}{b^{3}} + \frac{3 \,{\left (2 \, b^{2} x^{2} + 2 \, b x + 1\right )} e^{\left (-2 \, b x - 2 \, a\right )}}{b^{3}}\right )} c^{2} d^{2} - \frac{1}{8} \,{\left (4 \, x^{4} - \frac{{\left (4 \, b^{3} x^{3} e^{\left (2 \, a\right )} - 6 \, b^{2} x^{2} e^{\left (2 \, a\right )} + 6 \, b x e^{\left (2 \, a\right )} - 3 \, e^{\left (2 \, a\right )}\right )} e^{\left (2 \, b x\right )}}{b^{4}} + \frac{{\left (4 \, b^{3} x^{3} + 6 \, b^{2} x^{2} + 6 \, b x + 3\right )} e^{\left (-2 \, b x - 2 \, a\right )}}{b^{4}}\right )} c d^{3} - \frac{1}{80} \,{\left (8 \, x^{5} - \frac{5 \,{\left (2 \, b^{4} x^{4} e^{\left (2 \, a\right )} - 4 \, b^{3} x^{3} e^{\left (2 \, a\right )} + 6 \, b^{2} x^{2} e^{\left (2 \, a\right )} - 6 \, b x e^{\left (2 \, a\right )} + 3 \, e^{\left (2 \, a\right )}\right )} e^{\left (2 \, b x\right )}}{b^{5}} + \frac{5 \,{\left (2 \, b^{4} x^{4} + 4 \, b^{3} x^{3} + 6 \, b^{2} x^{2} + 6 \, b x + 3\right )} e^{\left (-2 \, b x - 2 \, a\right )}}{b^{5}}\right )} d^{4} - \frac{1}{8} \, c^{4}{\left (4 \, x - \frac{e^{\left (2 \, b x + 2 \, a\right )}}{b} + \frac{e^{\left (-2 \, b x - 2 \, a\right )}}{b}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.68257, size = 663, normalized size = 4.09 \begin{align*} -\frac{2 \, b^{5} d^{4} x^{5} + 10 \, b^{5} c d^{3} x^{4} + 20 \, b^{5} c^{2} d^{2} x^{3} + 20 \, b^{5} c^{3} d x^{2} + 10 \, b^{5} c^{4} x + 5 \,{\left (2 \, b^{3} d^{4} x^{3} + 6 \, b^{3} c d^{3} x^{2} + 2 \, b^{3} c^{3} d + 3 \, b c d^{3} + 3 \,{\left (2 \, b^{3} c^{2} d^{2} + b d^{4}\right )} x\right )} \cosh \left (b x + a\right )^{2} - 5 \,{\left (2 \, b^{4} d^{4} x^{4} + 8 \, b^{4} c d^{3} x^{3} + 2 \, b^{4} c^{4} + 6 \, b^{2} c^{2} d^{2} + 3 \, d^{4} + 6 \,{\left (2 \, b^{4} c^{2} d^{2} + b^{2} d^{4}\right )} x^{2} + 4 \,{\left (2 \, b^{4} c^{3} d + 3 \, b^{2} c d^{3}\right )} x\right )} \cosh \left (b x + a\right ) \sinh \left (b x + a\right ) + 5 \,{\left (2 \, b^{3} d^{4} x^{3} + 6 \, b^{3} c d^{3} x^{2} + 2 \, b^{3} c^{3} d + 3 \, b c d^{3} + 3 \,{\left (2 \, b^{3} c^{2} d^{2} + b d^{4}\right )} x\right )} \sinh \left (b x + a\right )^{2}}{20 \, b^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 7.34425, size = 660, normalized size = 4.07 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.24048, size = 505, normalized size = 3.12 \begin{align*} -\frac{1}{10} \, d^{4} x^{5} - \frac{1}{2} \, c d^{3} x^{4} - c^{2} d^{2} x^{3} - c^{3} d x^{2} - \frac{1}{2} \, c^{4} x + \frac{{\left (2 \, b^{4} d^{4} x^{4} + 8 \, b^{4} c d^{3} x^{3} + 12 \, b^{4} c^{2} d^{2} x^{2} - 4 \, b^{3} d^{4} x^{3} + 8 \, b^{4} c^{3} d x - 12 \, b^{3} c d^{3} x^{2} + 2 \, b^{4} c^{4} - 12 \, b^{3} c^{2} d^{2} x + 6 \, b^{2} d^{4} x^{2} - 4 \, b^{3} c^{3} d + 12 \, b^{2} c d^{3} x + 6 \, b^{2} c^{2} d^{2} - 6 \, b d^{4} x - 6 \, b c d^{3} + 3 \, d^{4}\right )} e^{\left (2 \, b x + 2 \, a\right )}}{16 \, b^{5}} - \frac{{\left (2 \, b^{4} d^{4} x^{4} + 8 \, b^{4} c d^{3} x^{3} + 12 \, b^{4} c^{2} d^{2} x^{2} + 4 \, b^{3} d^{4} x^{3} + 8 \, b^{4} c^{3} d x + 12 \, b^{3} c d^{3} x^{2} + 2 \, b^{4} c^{4} + 12 \, b^{3} c^{2} d^{2} x + 6 \, b^{2} d^{4} x^{2} + 4 \, b^{3} c^{3} d + 12 \, b^{2} c d^{3} x + 6 \, b^{2} c^{2} d^{2} + 6 \, b d^{4} x + 6 \, b c d^{3} + 3 \, d^{4}\right )} e^{\left (-2 \, b x - 2 \, a\right )}}{16 \, b^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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